5x^2+24x=36

Solution for 5x^2+24x=36 equation:

5x^2+24x=36

We move all terms to the left:

5x^2+24x-(36)=0

a = 5; b = 24; c = -36;
Δ = b2-4ac
Δ = 242-4·5·(-36)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*5}=\frac{-60}{10}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*5}=\frac{12}{10}
=1+1/5
$